(25)^4-2x=(1/125)^x+6

Solution for (25)^4-2x=(1/125)^x+6 equation:

(25)^4-2x=(1/125)^x+6

We move all terms to the left:

(25)^4-2x-((1/125)^x+6)=0


Domain of the equation: 125)^x+6)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-2x-((+1/125)^x+6)+25^4=0

We add all the numbers together, and all the variables

-2x-((+1/125)^x+6)+390625=0

We multiply all the terms by the denominator


-2x*125)^x+6)-((+390625*125)^x+6)+1=0

We add all the numbers together, and all the variables

-2x*125)^x+6)-(48828125^x+6)+1=0

Wy multiply elements

-250x^2=0

a = -250; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-250)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-500}=0$